Caute,
mam problem s tymto skriptom:
#!/bin/bash
function Info () {
echo "Pocet parametrov je $#"
for ARG in "$@"; do
echo $ARG
done
for ARG in "$*"; do
echo $ARG
done
}
function Sucet {
return $(( $1 + $2 ))
}
Rozdiel () {
return $(( $1 - $2 ))
}
Info 1 2 3 4 5 6
Sucet 3 5
echo $?
Rozdiel 9 7
echo $?
Pri spusteni vypise chybu na line14: return8: command not found
a tiez na line 18: return2: command not found
Vie niekto pomoct?
bash -command not found
Pre pridávanie komentárov sa musíte prihlásiť.
./dusan@debian:~/test$ ./script
Pocet parametrov je 6
1
2
3
4
5
6
1 2 3 4 5 6
8
2
Pocet parametrov je 6
1
2
3
4
5
6
1 2 3 4 5 6
8
2
Pocet parametrov je 6
1
2
3
4
5
6
1 2 3 4 5 6
./nazov_skriptu.sh: line 14: return8: command not found
127
./nazov_skriptu.sh: line 18: return2: command not found
127
return nenasiel? ako to.
Hod sem kedtak vypis: grep return ./skript
dakujem